[3.15] gh-62534: Document that three-argument type() does not call __prepare__ (GH-154028) - #154165
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…repare__ (pythonGH-154028) The three-argument form of type() skips the metaclass __prepare__ method, which is called by the class statement machinery rather than by the metaclass call itself. Say so in the type() entry and point to types.new_class() for dynamic class creation with the appropriate metaclass, as directed in the issue thread. (cherry picked from commit 5625b18) Co-authored-by: soreavis <263610811+soreavis@users.noreply.github.com>
This was referenced Jul 19, 2026
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The three-argument form of type() skips the metaclass prepare
method, which is called by the class statement machinery rather than
by the metaclass call itself. Say so in the type() entry and point to
types.new_class() for dynamic class creation with the appropriate
metaclass, as directed in the issue thread.
(cherry picked from commit 5625b18)
Co-authored-by: soreavis 263610811+soreavis@users.noreply.github.com